Seymour, Indiana has a population of 21,400, with a median household income of $52,100.
Current population data for Seymour.
21,400
$52,100
4.20%
$185,000
34.20
1000.00 Mbps
Seymour is a small local community located in Indiana. The city has a population that is above the average city population in Indiana, contributing to its local economic activity, housing demand, and infrastructure development. Population size can significantly influence transportation systems, commercial growth, educational services, and employment opportunities within the region.
Seymour is a notable city in Indiana, offering a mix of population dynamics, economic indicators, and housing trends.
Seymour has a population of 21,400, which is higher than the state average. This indicates a relatively larger urban presence within Indiana.
The median household income in Seymour is $52,100, which is below the state average, indicating moderate economic conditions.
The average housing price in Seymour is about $185,000, making it relatively affordable compared to many cities in Indiana.
The unemployment rate in Seymour is 4.20%, which is lower than the state average, indicating a relatively strong job market. Crime rates in Seymour are higher than the state average, which may be a factor for residents to consider.
Compared to other cities in Indiana, Seymour shows distinct differences in population size, economic activity, and housing affordability, making it a unique case for analysis.
Seymour continues to play a role in shaping regional trends in Indiana, particularly in terms of economic and demographic factors.
The population of Seymour is approximately 21,400.
Seymour offers a mix of economic conditions, housing affordability, and population size, making it suitable for different types of residents.
The median household income in Seymour is around $52,100.
The average housing price in Seymour is approximately $185,000.